Lessons

Eamcet Chemistry
1st Year : Unit 1.4 (Basics & Concepts) - Stoichiometric Calculations

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Q.

The mass of 80% pure H2 SO4 required to completely neutralise 60g of NaOH is nearly

View Answer

Correct choice: A

Explanation:

 2NaOH + H2 SO4 → Na2 SO4 + 2H2 O
2moles i.e 2X40=80gm NaOH is given by 98gm of H2 SO4
60gm NaOH is given by (60X98/80)= 73.5gm of H2 SO4
Wt.of 80% acid required= (73.5X100/80)= 91.875gm
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